work on returning search results in order

products/views.py

@@ -7,6 +7,7 @@ from functools import reduce
 from django.shortcuts import render
 from django.conf import settings
 from django.db.models import Q
+from django.core import serializers
 
 # Create your views here.
 from rest_framework import status
@@ -18,7 +19,7 @@ from rest_framework.decorators import api_view, permission_classes, action
 import requests
 
 from products.models import Product
-from products.serializers import ProductSerializer, TagFilterSerializer, ProductSearchSerializer
+from products.serializers import ProductSerializer, TagFilterSerializer
 from companies.models import Company
 from history.models import HistorySync
 
@@ -162,9 +163,12 @@ def product_search(request):
 
             # extract filters from result_set
             filters = extract_search_filters(result_set)
-            # serialize and respond
-            product_serializer = ProductSearchSerializer(result_set, many=True, context={'request': request})
-            # TODO: send product data in order by rank value
-            return Response(data={"filters": filters, "products": product_serializer.data})
+            # order results and respond
+            result_list = list(result_set)
+            ranked_products = sorted(result_list, key= lambda rank:rank.rank, reverse=True)
+            # TODO: slice ranked_products as per pagination
+            import ipdb; ipdb.set_trace()
+            data = serializers.serialize('json', ranked_products)
+            return Response(data={"filters": filters, "products": data})
       except Exception as e:
             return Response({"errors": {"details": str(e)}}, status=status.HTTP_500_INTERNAL_SERVER_ERROR)